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Question

If the foot of the perpendicular from point (4,3,8) on the line L1:xal=y23=zb4,
l0 is (3,5,7), then the shortest distance between the line L1 and line L2:x23=y44=z55 is equal to :

A
23
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B
13
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C
12
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D
16
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Solution

The correct option is D 16
(3,5,7) lies on given line L1.
Then 3al=33=7b4
7b4=1b=3
3al=13a=l
A(4,3,8) and B(3,5,7)
DR's of AB is (1,2,1)
AB line L1
(1)(l)+(2)(3)+4(1)=0
l=2
a=1

a=1,b=3,l=2
x12=y23=z34
x23=y44=z55
Shortest distance=∣ ∣122234345∣ ∣∥ ∥ ∥^i^j^k234345∥ ∥ ∥=16

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