Question

If the foot of the perpendicular from the origin to a straight line is the point $(3,-4)$. Then the equation of the line is

Answer 1

Slope of line passing through origin and $(3,-4)$ is $(-4-0)/(3-0)=-4/3$

Slope of normal to this line$=3/4$

Now equation of line with slope $3/4$ and passing through $(3,-4)$ is

$y+4=3(x-3)/4$

$4(y+4)=3x-9$

$4y+16=3x-9$

$4y=3x-25$.