If the force on a rocket moving in force free space with an exhaust velocity of gases $300 m / s e c$ is $210 N$ , then the rate of combustion of fuel, is:

0.7 k g / s

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1.4 k g / s

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2.7 k g / s

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10.7 k g / s

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Solution

The correct option is A $0.7 k g / s$
$F = (\frac{d m}{d t}) \times v$
$210 = (\frac{d m}{d t}) \times 300$
$∴ \frac{d m}{d t} = \frac{210}{300} = 0.7 k g / s$

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