Question

If the fractions $\frac{4}{5}$, $\frac{7}{9}$, $\frac{5}{6}$, $\frac{8}{9}$, $\frac{6}{11}$, and $\frac{10}{11}$, are arranged in ascending order of their values, which one will be the third?

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Given fractions = $\frac{4}{5}$, $\frac{7}{9}$, $\frac{5}{6}$, $\frac{8}{9}$, $\frac{6}{11}$ and $\frac{10}{11}$

Or $\frac{4}{5}$ = 0.8

Or $\frac{7}{9}$ = 0.78

Or $\frac{5}{6}$ = 0.83

Or $\frac{8}{9}$ = 0.89

Or $\frac{6}{11}$ = 0.545

Or $\frac{10}{11}$ = 0.91

Now 0.545 < 0.78 < 0.8 < 0.83 < 0.89 < 0.91

So, $\frac{6}{11}$ < $\frac{7}{9}$ < $\frac{4}{5}$ < $\frac{5}{6}$ < $\frac{8}{9}$ < $\frac{10}{11}$

So, the required number is $\frac{4}{5}$.