1
Question
If the frequency of a recessive allele is 0.4. What will be the frequency of heterozygote carriers in a population of 2000?
If the frequency of a recessive allele is 0.4. What will be the frequency of heterozygote carriers in a population of 2000?
Open in App
Solution
The correct option is A 960
Assuming that the population is in the Hardy - Weinberg equilibrium, let’s suppose the frequency of the recessive allele is represented by q.
Then q = 0.4
We know p + q = 1
p + 0.4 = 1
p = 1 - 0.4
p = 0.6
To calculate the heterozygote frequency 2pq
2pq = 2×0.6×0.4
2pq = 0.48
To calculate the number of heterozygous individual:
heterozygote frequency is multiplied by the total number of individuals
0.4×2000 = 960
So there are 960 carriers in a population of 2000 for the given gene.
Assuming that the population is in the Hardy - Weinberg equilibrium, let’s suppose the frequency of the recessive allele is represented by q.
Then q = 0.4
We know p + q = 1
p + 0.4 = 1
p = 1 - 0.4
p = 0.6
To calculate the heterozygote frequency 2pq
2pq = 2×0.6×0.4
2pq = 0.48
To calculate the number of heterozygous individual:
heterozygote frequency is multiplied by the total number of individuals
0.4×2000 = 960
So there are 960 carriers in a population of 2000 for the given gene.
Suggest Corrections
7
Similar questions