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Question

# If the frequency of a recessive allele is 0.4. What will be the frequency of heterozygote carriers in a population of 2000?

A
960
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B
1000
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C
1960
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D
940
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Solution

## The correct option is A 960Assuming that the population is in the Hardy - Weinberg equilibrium, let’s suppose the frequency of the recessive allele is represented by q. Then q = 0.4 We know p + q = 1 p + 0.4 = 1 p = 1 - 0.4 p = 0.6 To calculate the heterozygote frequency 2pq 2pq = 2×0.6×0.4 2pq = 0.48 To calculate the number of heterozygous individual: heterozygote frequency is multiplied by the total number of individuals 0.4×2000 = 960 So there are 960 carriers in a population of 2000 for the given gene.

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