Question

If the frequency of dominant allele is 60%, find out the percentage of heterozygous individuals in the population.

• A. 45 %
• B. 47 %
• C. 48 %
• D. 50 %

Answer 1

The correct option is C 48 %

Frequency of dominant allele (p) = 60% = 0.6
The frequency of recessive allele, according to (p + q) = 1, will be 0.4
The value of pq = 0.6 × 0.4 = 0.24
The frequency of heterozygous individuals, therefore, will be 2pq = 2 × 0.24 = 0.48 or 48%.