If the frequency of the 2nd and 5th harmonics of string fixed at both ends differ by 108Hz. What is the fundamental frequency of the string?
A
18Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
36Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
72Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C36Hz Frequency of vibration in a string fixed at both ends is given by f=nv2L
Fundamental frequency f=v2L
For second harmonic, f2=2v2L=2f
For fifth harmonic, f5=5v2L=5f
From the data given in the question, 5f−2f=108⇒3f=108 ⇒f=36Hz