If the frequency of the particle performing circular motion increases from 60 rmp to 180 rpm is 20 seconds, its angular acceleration is
A
0.1 rad/s2
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B
3.142 rad/s2
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C
0.6284 rad/s2
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D
0.3142 rad/s2
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Solution
The correct option is A 0.1 rad/s2 Given that, convert 60rpm into 1rad/s and convert 180rpm into 3rad/s thus a is equal to 3rad/s−1rad/s/20 =2/20 =1/10 =0.1rad/s2