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Question

If the frequency or revolution of the electron in first Bohr orbit of a H-atom is 6.6×1015 Hz, the frequency in the next orbit is

A
13.2×1015 Hz
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B
43.50×1030 Hz
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C
0.8×1015 Hz
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D
1.65×1015 Hz
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Solution

The correct option is A 13.2×1015 Hz
Frequency of nth orbit in Hatom is given by :-
νn=nν0 (ν0= frequency of first orbit)
so for n = 2
ν2=2×6.6×1015=13.2×1015H2

1101244_1173781_ans_94e1173a41464f81a66063e000c5bb26.JPG

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