If the frog wants to jump to the direction of the LCM of 6 and 9, where should it land?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 18
Using the ladder mathod, the LCM of 6 and 9 is:
LCM (6, 9): 2 × 3 × 3 = 18

Hence, the frog should land on 18.

Suggest Corrections

Similar questions

Q. A frog jumps 2 m in a single jump. How much distance will it able to cover in 9 jumps?

Q. If Aryan wants to grow beans, cauliflower, and cabbage on same plot of land, what type of soil should the plot have?

Q. A frog sits on the end of a long board of length

L = 10 c m

. The board rests on frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is minimum take of speed

v

m s^{- 1}

relative to the ground that the frog follows to do the tricks ? [Assume that the board and frog have equal masses?]

Q. A frog sits on the end of a ball board of length

L = 5 m

. The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is the minimum take-off speed (in m/s), i.e., relative to ground 'v' that allows the frog to do the trick? The board and the frog have equal masses

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

Join BYJU'S Learning Program

If the frog wants to jump to the direction of the LCM of 6 and 9, where should it land?

The correct option is C 18Using the ladder mathod, the LCM of 6 and 9 is: LCM (6, 9): 2 × 3 × 3 = 18 Hence, the frog should land on 18.

The correct option is C 18
Using the ladder mathod, the LCM of 6 and 9 is:
LCM (6, 9): 2 × 3 × 3 = 18

Hence, the frog should land on 18.