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Question

If the function F:RR defined by f(x)=3x+3x2,then show that f(x+y)+f(xy)=2f(x)f(y)

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Solution

f(x)=12[3x+13x]

f(x+y)=12[3x.3y+13x.3y]

f(xy)=12[3x3y+3y3x]

f(x+y)+f(xy)=12[3x.3y+3x3y+13x.3y+3y3x]

=12[3x[3y+13y]+13x[13y+3y]]

=12[(3x+13x)(3y+13y)]

=2.f(x).f(y)

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