The correct options are
A f(x) is an even function
C If f(2)=a, then f(−2)=a
f(x+y)+f(x−y)=2f(x)f(y) ....[1]
Putting x=0 in [1], we get
f(y)+f(−y)=2f(0)f(y) ....[2]
Putting x=0,y=0 in [1], we get
f(0)+f(0)=2f(0)f(0)⇒f(0)=1
(As f(0)≠0)
∴f(−y)=f(y) (From[2])
Hence, the function is even.
Then, f(−2)=f(2)=a