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Byju's Answer
Standard XII
Mathematics
Single Point Continuity
If the functi...
Question
If the function
f
(
x
)
=
⎧
⎨
⎩
a
|
π
−
x
|
+
1
,
x
≤
5
b
|
x
−
π
|
+
3
,
x
>
5
is continuous at
x
=
5
, then the value of
a
−
b
is :
A
2
π
−
5
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B
2
π
+
5
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C
2
5
−
π
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D
−
2
π
+
5
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Solution
The correct option is
C
2
5
−
π
f
(
x
)
=
⎧
⎨
⎩
a
|
π
−
x
|
+
1
,
x
≤
5
b
|
x
−
π
|
+
3
,
x
>
5
is continuous at
x
=
5
∴
lim
x
→
5
−
f
(
x
)
=
lim
x
→
5
+
f
(
x
)
=
f
(
5
)
⇒
a
|
π
−
5
|
+
1
=
b
|
5
−
π
|
+
3
⇒
a
(
5
−
π
)
+
1
=
b
(
5
−
π
)
+
3
⇒
(
a
−
b
)
(
5
−
π
)
=
2
or,
a
−
b
=
2
5
−
π
Suggest Corrections
16
Similar questions
Q.
If the function
f
(
x
)
=
⎧
⎨
⎩
a
|
π
−
x
|
+
1
,
x
≤
5
b
|
x
−
π
|
+
3
,
x
>
5
is continuous at
x
=
5
, then the value of
a
−
b
is :
Q.
If the function
f
(
x
)
=
⎧
⎨
⎩
a
|
π
−
x
|
+
1
,
x
≤
5
b
|
x
−
π
|
+
3
,
x
>
5
is continuous at
x
=
5
, then the value of
a
−
b
is
[1 mark]
Q.
If the function
f
(
x
)
=
{
a
|
π
−
x
|
+
1
,
x
≤
5
b
,
|
π
−
x
|
+
3
,
x
>
5
is continuous at
x
=
5
then the value of
a
−
b
is:
Q.
If
f
(
x
)
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
(
1
−
sin
3
x
)
3
cos
2
x
,
x
<
π
2
a
,
x
=
π
2
b
(
1
−
sin
x
)
(
π
−
2
x
)
2
,
x
>
π
2
is continuous at
x
=
π
2
, then the value of
(
b
a
)
5
/
3
is
Q.
If
f
(
x
)
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
(
6
5
)
t
a
n
6
x
t
a
n
5
x
;
0
<
x
<
π
2
a
+
2
;
x
=
π
2
(
1
+
|
c
o
t
x
|
)
b
|
t
a
n
x
|
a
;
π
2
<
x
<
π
is continuous at
x
=
π
2
. Then the values of
a
and
b
are
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Single Point Continuity
Standard XII Mathematics
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