wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the function f(x)=x2(A+2)x+Ax2for x22for x=2 is
continuous at x=2 , then

A
A=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
A=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A A=0
Since, the denominator goes to 0 as x approaches 2
The function should be of 00 form
Hence as x goes to 2,x2(A+2)x+A goes to 0
=42(A+2)+A=0
A=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative of Standard Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon