If the function f(x)=⎧⎪
⎪
⎪⎨⎪
⎪
⎪⎩x+a2√2sinx,0≤x<π4xcotx+b,π4≤x≤π2bsin2x−acos2x,π2<x≤π is continuous in the interval [0,π] Then the values of (a, b) are I. (-1, -1) II. (0, 0) III. (-1, 1) IV. (1, 1)
A
I and II are correct
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B
II and IV are correct
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C
III and IV are correct
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D
None of these
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Solution
The correct option is BII and IV are correct limx→π+4f(x)=limx→π−4f(x)⇒a2=b and limx→π+2f(x)=limx→π−4f(x)⇒a=b