If the function f(x)=[(x−3)2a]sin(x−3)+acos(x−3) is continuous in [4,8], then the range of a is ([.] denotes the greatest integer function)
A
a<25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a>25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a<30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a>30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ba>25 We know that sin(x−3) and cos(x−3) are continuous for all values of x. [x2] is discontinuous at integral points. f(x) is continuous in [4,8] if [(x−3)2a]=0∀x∈[4,8] Now, (x−3)2∈[1,25] for x∈[4,8] ⇒a>25 for [(x−3)2a]=0