If the function f(x)=[(x−3)2a]sin(x−3)+acos(x−3) is continuous in [4,8], then the range of a is
([.] denotes the greatest integer function)
A
a<25
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B
a>25
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C
a<30
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D
a>30
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Solution
The correct option is Ba>25 We know that sin(x−3) and cos(x−3) are continuous for all values of x. [x2] is discontinuous at integral points. f(x) is continuous in [4,8] if [(x−3)2a]=0∀x∈[4,8]
Now, (x−3)2∈[1,25] for x∈[4,8] ⇒a>25 for [(x−3)2a]=0