Question

If the function f(x) satisfies $\underset{x\to 1}{lim}\frac{f\left(x\right)-2}{x^2-1}=\pi ,then\underset{x\to 1}{lim}f\left(x\right)=$

• A. 1
• B. 2
• C. 0
• D. 3

Answer 1

The correct option is B

2

$\underset{x\to 1}{lt}\frac{f\left(x\right)-2}{x^2-1}=\pi \Rightarrow \underset{x\to 1}{lt}f\left(x\right)=2$
$\Rightarrow f\left(1\right)=2$