If the function f(x)= x3-3ax2+b is strictly increasing derivative for x > 0, then which of the following is always true?
f(x) = x3 -3ax2 + b
f'(x) = 3x2 - 6ax
for f(x) to be increasing f'(x) > 0.
3x2 - 6ax > 0
3x (x - 2a) > 0
(x - 2a) > 0 [There fore x > 0]
x > 2a
So, a ≥0