Fthe function g x - x 200-200- x 199-199- x 198-198- x 2-2- x -5- then g -0-A- 200B- 1- 5D- 100

G(x)=x^200200+x^199199+x^198198+⋯+x^22+x+5 Then, g'(x)=x^199+x^198+x^197+⋯+x+1 ∴ g'(0)=1 ...

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Standard XII

Mathematics

Binomial Expression

fthe function...

Question

If the function $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) =$

1

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100

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5

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Solution

The correct option is A $1$
$g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5$

$Then, g^{'} (x) = x^{199} + x^{198} + x^{197} + \dots + x + 1$

$∴ g^{'} (0) = 1$

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Similar questions

Q. If the function

g (x)

is defined by

g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + . . . . + \frac{x^{2}}{2} + x + 5

, then

g^{'} (0) =

_____

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

Q. Let

N = 2^{200} (^{200} C_{0}) (^{200} C_{100}) - 2^{198} (^{200} C_{1}) (^{199} C_{99}) + 2^{196} (^{200} C_{2}) (^{198} C_{98}) + \dots + (^{200} C_{100}) (^{100} C_{0})

then -

Q. If

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where

g (x) = x^{3} + t a n x + [\frac{x^{2} + 1}{p}]

is a odd function then the value of parametric P is

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If the function g(x)=x200200+x199199+x198198+⋯+x22+x+5, then g′(0)=

The correct option is A 1 g(x)=x200200+x199199+x198198+⋯+x22+x+5 Then, g′(x)=x199+x198+x197+⋯+x+1 ∴g′(0)=1

If the function $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) =$

The correct option is A $1$
$g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5$

$Then, g^{'} (x) = x^{199} + x^{198} + x^{197} + \dots + x + 1$

$∴ g^{'} (0) = 1$