If the function y=sin(f(x)) is monotonic in an interval of x[where f(x) is continuous] and the difference between the maximum and minimum value of f(x) is kπ, then the value of (k+1) is
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Solution
As, y=sin(f(x)) is monotonic for f(x)∈[2nπ−π2,2nπ+π2] or [2nπ+π2,2nπ+3π2] ∴ difference between the maximum and minimum value of f(x) is π ⇒k=1