Question

If the galvanometer reading is zero in the gives circuit, the current passing through resistance $250\Omega$ is

• A. 0.016 A
• B. 0.16 A
• C. 0.032 A
• D. 0.042 A

Answer 1

The correct option is A 0.016 A

No current through galvanometer

So remove -G- from circuit

Current$=\frac{12}{750}=0.016$A