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Question

If x2+x3x-1-x+32x+12+x2x3-3x-3x2+43x=a0+a1x+......+a7x7 then the value of a0 is


A

35

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B

24

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C

23

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D

22

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E

21

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Solution

The correct option is E

21


Explanation for the correct option

Determinant:

It is given that x2+x3x-1-x+32x+12+x2x3-3x-3x2+43x=a0+a1x+......+a7x7.

Put x=0 in both sides of the equation.

⇒02+030-1-0+320+12+0203-30-302+430=a0+a10+......+a707⇒0-1312-3-340=a0⇒a0=02×0--3×4--11×0--3×-3+31×4--3×2⇒a0=0-9+34+6⇒a0=30-9⇒a0=21

Therefore, the value of a0 is 21.

Hence, option(E) is the correct option


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