wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x2+x3x-1-x+32x+12+x2x3-3x-3x2+43x=a0+a1x+......+a7x7 then the value of a0 is


A

35

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

23

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

22

No worries! We‘ve got your back. Try BYJU‘S free classes today!
E

21

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is E

21


Explanation for the correct option

Determinant:

It is given that x2+x3x-1-x+32x+12+x2x3-3x-3x2+43x=a0+a1x+......+a7x7.

Put x=0 in both sides of the equation.

⇒02+030-1-0+320+12+0203-30-302+430=a0+a10+......+a707⇒0-1312-3-340=a0⇒a0=02×0--3×4--11×0--3×-3+31×4--3×2⇒a0=0-9+34+6⇒a0=30-9⇒a0=21

Therefore, the value of a0 is 21.

Hence, option(E) is the correct option


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Modulus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon