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Question

If the given four electronic configurations
(i) n = 4, l = 1
(ii) n = 4, l = 0
(iii) n = 3, l = 2
(iv) n = 3, l = 1
are arranged in order of increasing energy, then the order will be:

A
(iv) < (ii) < (iii) < (i)
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B
(ii) < (iv) < (i) < (iii)
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C
(i) < (iii) < (ii) < (iv)
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D
(iii) < (i) < (iv) < (ii)
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