Multi-Electron Configurations and Orbital Diagrams
If the given ...
Question
If the given four electronic configurations (i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n = 3, l = 2 (iv) n = 3, l = 1 are arranged in order of increasing energy, then the order will be:
A
(iv) < (ii) < (iii) < (i)
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B
(ii) < (iv) < (i) < (iii)
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C
(i) < (iii) < (ii) < (iv)
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D
(iii) < (i) < (iv) < (ii)
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Solution
The correct option is B (iv) < (ii) < (iii) < (i) (i) n = 4, l = 1 4p orbital (ii) n = 4, l = 0 4s orbital (iii) n = 3, l = 2 3d orbital (iv) n = 3, l = 1 3p orbital