Question

If the Given limit: $\underset{x\to 4}{lim}\frac{4x+3}{x-2}$ has value $\frac{k}{2}.$Find the value of $k.$

Answer 1

$\underset{x\to 4}{lim}\frac{4x+3}{x-2}$ $=\frac{4\left(4\right)+3}{4-2}$

$=\frac{16+3}{2}$

$=\frac{19}{2}$

Equating with $\frac{k}{2}$

we get, $k=19$