If the given system of equation is 3x + 2y = 2xy; 6x + 2y = 3xy, then the first step to solve such eqs is

To equate the coefficients of y

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To equate the coefficients of x

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Add or subtract the two equation

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To divide the complete equation by xy

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Solution

The correct option is D
To divide the complete equation by xy

Unless we have a constant in the given eqs, we will not be able to solve the system. 2xy & 3xy are not the constants. Hence we divide the complete equation by xy.

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Similar questions

\frac{2}{3 x + 2 y} + \frac{3}{3 x - 2 y} = \frac{17}{5}

\frac{5}{3 x + 2 y} + \frac{1}{3 x - 2 y} = 2

x, y ϵ R

4 x^{2} + 3 x y + (2 x y - 3 x^{2}) i = 4 y^{2} - (\frac{x^{2}}{2}) + (3 x y - 2 y^{2}) i

Solve the following systems of equations:

$\frac{2}{3 x + 2 y} + \frac{3}{3 x - 2 y} = \frac{17}{5}$

$\frac{5}{3 x + 2 y} + \frac{1}{3 x - 2 y} = 2$

3 x + y = 6

6 x + 2 y = 3

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