If the given triangles △ABC and △PQR are similar, then find the lengths of the sides x and y.

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Solution

∆ABC and ∆PQR are similar.
Therefore,
$\frac{A B}{P Q} = \frac{B C}{Q R} = \frac{C A}{R P}$ (side ratio)
$\frac{4}{2} = \frac{x}{3} = \frac{8}{y} = 2$
$x = 6$ cm and $y = 4$ cm

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If the given triangles △ABC and △PQR are similar, then find the lengths of the sides x and y.

∆ABC and ∆PQR are similar. Therefore, ABPQ=BCQR=CARP (side ratio) 42=x3=8y=2 x=6 cm and y=4 cm

∆ABC and ∆PQR are similar.
Therefore,
$\frac{A B}{P Q} = \frac{B C}{Q R} = \frac{C A}{R P}$ (side ratio)
$\frac{4}{2} = \frac{x}{3} = \frac{8}{y} = 2$
$x = 6$ cm and $y = 4$ cm