If the graph of $2 x + k y = 10 k$ intersects $x$ -axis at $(2, 0)$ find $k$

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Solution

Given $2 x + k y = 10 k$ intersects $x -$ axis at $(2, 0)$
$⟹ (2, 0)$ lies on this line
$2 (2) + k (0) = 10 k$
$⟹ k = \frac{4}{10} = \frac{2}{5}$

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