If the graph of $a x^{2} + b x + c$ is given as

Then the graph of $a {(x - h)}^{2} + b {(x - h)}^{2} + c = 0$

Where $h > 0$ , will be

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Solution

The correct option is C

The graph will get shifted by $h$ units to the right when we replace $x$ by $x - h$ . The minimum value will be the same.

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Similar questions

If the graph of a $x^{2}$ + bx + c is given as

Then the graph of a ${(x - h)}^{2}$ + b ${(x - h)}^{2}$ + c = 0

Where h > 0, will be

b^{2} - 4 a c > 0

y = a x^{2} + b x + c

b^{2} - 4 a c = 0

y = a x^{2} + b x + c

y = a x^{2} + b x + c = 0

a x^{2} + b x + c,

a > 0

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