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Question

If the graph of |y|=f(x), where f(x)=ax2+bx+c; b&cϵR; a0, has the maximum vertical height 4, then

A
a>0
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B
a<0
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C
(b24ac) is negative
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D
Nothing can be said
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Solution

The correct option is B a<0
Given : Graph of |y|=f(x) , where ax2+bx+c has maximum vertical height 4
To find : The condition of a
Solution : All quadratic functions have a U-shaped graph called a parabola.
The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate denoted by x=b2a
The y-coordinate of the vertex is the maximum or minimum value of the function.
If the y-coordinate has maximum value then parabola opens down, and a<0

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