The correct option is D (0,1e)
Given curves are y=lnx and y=ax.
⇒lnx=ax has exactly two solutions.
⇒lnxx=a has exactly two solutions to find the range of lnxx.
Let y=lnxx,x>0
dydx=x.1x−lnxx2=1−lnxx2
y is increasing, if 1−lnx>0 or lnx<1
⇒0<x<e
Range of y∈(−∞,1e) graph of y=lnxx
For exactly two solutions of lnxx=a
⇒a∈(0,1e)