Question

If the gravitational constant is expressed in terms of $dynes{m}^{-2}k{g}^2$, how will the value of G change:

• A. $6.67\times {10}^{-11}dynesk{g}^2{m}^{-2}$
• B. $6.67\times {10}^{-8}dynesk{g}^2{m}^{-2}$
• C. $6.67\times {10}^{-6}dynesk{g}^2{m}^{-2}$
• D. $6.67\times {10}^{-3}dynesk{g}^2{m}^{-2}$

Answer 1

Answer: (C)

$6.67\times {10}^{-6}dynesk{g}^2{m}^{-2}$

'G' is expressed as

$G=6.67\times {10}^{-11}N.m^{-2}.{kg}^{+2}\therefore 1N={10}^{5}dyne1m={10}^{2}cm1kg={10}^{3}g.$

$G=6.67\times {10}^{-11}\times {10}^{5}dynes.kg.m^{-2}$ [As,$1N={10}^5$dyne]