Question

If the gravitational field intensity at a point is given by $g=\frac{GM}{r^{2.5}}$Then the potential at distance $r$ is

• A. $\frac{-2GM}{3r^{1.5}}$
• B. $\frac{-GM}{r^{3.5}}$
• C. $\frac{GM}{3r^{1.5}}$
• D. $g=\frac{GM}{r^{3.5}}$

Answer 1

The correct option is A $\frac{-2GM}{3r^{1.5}}$

$V=\int Edr$

$V={\int }_{infinity}^r\frac{GM}{r^{2.5}}dr$

$V=\frac{2GM}{3}[-\frac{1}{r^{1.5}}{]}_{infinity}^r$

$V=-\frac{2GM}{3r^{1.5}}$