If the gravitational force between two spheres is 400N, and the distance between them is doubled, the force will be ____________
A
400N
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B
200N
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C
100N
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D
40N
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Solution
The correct option is C100N Given, r2=2r1 From Newtons law of Gravitation, F1=GM1M2(r1)2 and F2=GM1M2(r2)2 or, F1F2=GM1M2(r1)2×(r2)2GM1M2 or, F1F2=(r2)2(r1)2 or, F1F2=(2r1)2(r1)2 or, F2=F14=4004=100N