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Question

If the ground is smooth, what is the total kinetic energy of body at t=2s. Initially, the body was at rest.

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A
25J
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B
16.67J
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C
50J
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D
37.5J
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Solution

The correct option is C 50J
τo=IOα
F(2R)FR=IαFR=Iα
10×1=4α gives α=2.5rad/s2
Now w=wi+α(t)
w=0+2.5(2)=5rad/s
K.E=12Iw2=12×4(5)2
K.E=50J

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