Question

If the H.M. between two numbers is 16/5, their A.M. is A, G.M. is G and $2A+G^2=26$, then the numbers are

• A. $6,8$
• B. $4,8$
• C. $2,8$
• D. $1,8$

Answer 1

The correct option is C $2,8$

$G{M}^2/AM=HM$
Now given $G{M}^2=26-2A$
So $(26-2A)/A=16/5$
On solving we get $A=5$
So $G=4$
Let the number be $a,b$ .Then $a+b=10$
and $\sqrt{ab}=4$
Only option C follows both the conditions