Question

If the half-cell reaction $A+e^{-}⟶A^{-}$ has a large negative reduction potentials, it follows that:

• A. $A$ is readily reduced
• B. $A$ is readily oxidised
• C. $A^{-}$ is readily reduced
• D. $A^{-}$ is readily oxidised

Answer 1

The correct option is D $A^{-}$ is readily oxidised

The more negative the potential is the more likely the element will be oxidized. Hence, $A^{-}$ is readily oxidized.