Question

If the heat 110 J is added to a gaseous system and it acquires internal energy of 40 J, then the amount of internal work done is

• A. 40 J
• B. 70 J
• C. 150 J
• D. 110 J

Answer 1

The correct option is B

70 J

Here, $dQ=110J,dU=40J$

From $dQ=dU+dW$

$dW=dQ–dU=110–40=70J$