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Question

If the heat of neutralisation for a strong acid-base reaction is -57.1 kJ. What would be the heat released when 350 cm3of 0.20 M H2SO4 is mixed with 650 cm3 of 0.10 M NaOH.


A
8.5 kJ
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B
17.1 kJ
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C
5.7 kJ
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D
3.71 kJ
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E
2.85 kJ
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Solution

The correct option is C 3.71 kJ
Moles of H2SO4=M×V=0.20×350=70 mmol

Moles of H+ ions =2×70=140 mmol

Moles of NaOH=M×V=0.10×650=65 mmol

Moles of OH ions =65 mmol

Thus, NaOH is the limiting reactant. As such 65 mmol of OH ions will react with 65 mmol of H+ ions to give 65 mmol of water.

1 mol of H+ ions react with 1 mol of OH ions to give 1 mol of H2O and in the process 57.1 kJ of heat is produced.

Thus heat produced =65×57.11000=3.71 kJ

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