If the height and base of the right triangle is 12 cm and 9 cm respectively, then the area of the triangle is __ $c m^{2}$ .

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Solution

For a right angled triangle, the area of the triangle = $\frac{1}{2} \times h e i g h t \times b a s e$

Therefore, the area of the triangle:
$= \frac{1}{2} \times 12 \times 9$
$= 54 c m^{2}$

Therefore the area of the triangle is 54 $c m^{2}$

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If the height and base of the right triangle is 12 cm and 9 cm respectively, then the area of the triangle is __ cm2.

For a right angled triangle, the area of the triangle = 12×height×base Therefore, the area of the triangle: =12×12×9 =54cm2 Therefore the area of the triangle is 54 cm2

If the height and base of the right triangle is 12 cm and 9 cm respectively, then the area of the triangle is __ $c m^{2}$ .

For a right angled triangle, the area of the triangle = $\frac{1}{2} \times h e i g h t \times b a s e$

Therefore, the area of the triangle:
$= \frac{1}{2} \times 12 \times 9$
$= 54 c m^{2}$

Therefore the area of the triangle is 54 $c m^{2}$