If the height and diameter of a right circular cylinder are 32 cm and 6 cm respectively, then the radius of the sphere whose volume is equal to the volume of the cylinder is
Volume of a Cylinder of Radius "R" and height "h" =πR2h
Radius of the cylinder =62=3cm
Hence, volume of the given cylinder =π×3×3×32cm3
Now, Volume of a sphere of radius 'r' =43πr3
$\Rightarrow \dfrac { 4 }{ 3 } \pi { r
}^{ 3 } = \pi \times 3\times 3\times 32$
$\Rightarrow { r }^{ 3 } = 3 \times 3 \times 3 \times 8$
=>r=3×2=6cm