Question

If the height of a bucker in the shape of frustum of a cone is $16cm$ and the diameters of its two circumends are $40cm$ and $16cm$,then its slant height is

• A. $20cm$
• B. $12\sqrt{5}cm$
• C. $8\sqrt{1}3cm$
• D. $16cm$

Answer 1

The correct option is A $20cm$

Let Slant Height be the Hypotenuse of a Imaginary Right angled Triangle whose height will be equal to that of the frustum and its base will be equal to $\frac{40}{2}-\frac{16}{2}=20-8=12$

Hence, According to Pythagoras theorem

$S{H}^2={16}^2+{12}^2$
$=400$

$\Rightarrow SH=\sqrt{400}cm=20cm$