If the height of a bucket in the shape of frustum of a cone is 16 cm and the diameters of its two circular ends are 40 cm and 16 cm then its slant height is

(a) 20 cm (b) $12 \sqrt{5} c m$ (c) $8 \sqrt{13} c m$ (d) 16 cm

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Solution

As we know
Slant height of the frustum is given by formula

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If the height of a bucket in the shape of frustum of a cone is 16 cm and the diameters of its two circular ends are 40 cm and 16 cm then its slant height is (a) 20 cm (b) 12√5 cm (c) 8√13 cm (d) 16 cm

As we know Slant height of the frustum is given by formula

If the height of a bucket in the shape of frustum of a cone is 16 cm and the diameters of its two circular ends are 40 cm and 16 cm then its slant height is

(a) 20 cm (b) $12 \sqrt{5} c m$ (c) $8 \sqrt{13} c m$ (d) 16 cm

As we know
Slant height of the frustum is given by formula