Question

If the height of a pole is $6m$ and the length of its shadow is $2\sqrt{3}m$, then the angle of elevation of sun is equal to

• A. ${60}^0$
• B. ${45}^0$
• C. ${30}^0$
• D. ${90}^0$

Answer 1

The correct option is A ${60}^0$

Let $AB$ is a pole of height $6m$

Length of a shadow of pole $BC=2\sqrt{3}m$

Let angle of elevation of sun $\angle ACB=\theta$

From right angled $\Delta ABC$,

$\tan \theta =\frac{AB}{BC}$

$\tan \theta =\frac{6}{2\sqrt{3}}$

$\tan \theta =\sqrt{3}$

$\tan \theta =\tan {60}^0$

$\theta ={60}^0$

So, correct choice is (A).