If the highest modulating frequency of the wave is 5kHz, the number of stations that can be accommodated in a 150kHz bandwidth are
A
15
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B
10
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C
5
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D
none of these
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Solution
The correct option is D15 In case of complex audio signals, bandwidths (B.W)=2 × maximum frequency of modulating signal =2×5kHz=10kHz This is B.W for one channel ∴ No.of stations =TotalB.WB.Wforeachchannel=150kHz10kHz=15