If the hypotenuse of a right-angled triangle is 13 and it's inradius is 5, then it's area = _____.
90 cm2
Let PB = BQ = r
AP = AR = b - r
CQ = CR = a - r
AR + CR = h
a + b - 2r = h
a + b = h + 2r
Area = A = rS
⇒ A = ra+b+h2
⇒ A = rh+2r+h2
⇒ A = r(h + r)
⇒ A = 5(13 + 5) = 5(18) = 90 cm2