Question

If the identify of methanol is $0.793kg$ $L^{-1}$, what is its volume needed for making $2.5L$ of its $0.25M$ solution?

Answer 1

Molar mass of methanol $\left(C{H}_{3}OH\right)=32mo{l}^{-1}=0.032kgmo{l}^{-1}$

Molarity of the solution$=\frac{0.793}{0.032}=24.78mol{L}^{-1}$

Now, $M_1{V}_1=M_2{V}_{2}24.78\times V_1=0.25\times 2.5V_1=25.22mL$