Question

If the image of the point (1, 1, 1) with respect to a plane ax + by + cz + d = 0 is (3, –1, 5), then

• A. c< d < a < b
• B. d < a < b < c
• C. b < d < c < a
• D. d < b < a < c

Answer 1

The correct option is D

d < b < a < c

Plane is passing through (2, 0,3) . DRs of normal = (1, –1, 2)

$\therefore$ Equation of the plane is 1(x – 2) – 1(y – 0) + 2(z – 3) = 0

$\Rightarrow$ x – y + 2z – 8 = 0