If the image of the point (2, 1) with respect to a line mirror is (5, 2), find the equation of the mirror.
Here,
Let l be line mirror and B is image of A
Let m be slope of line l
So,
m(slope of AB)=−1
m(2−15−2)=−1
m(13)=−1
m=−3
M is mid point of AB
M=(2+52,2+12)
M=(72,32)
Equation line l is,
y−y1=m(x−x1)
y−32=(−3)(x−72)
2y−32=−3x+212
2y−3=−6x+21
6x+2y=24
3x+y=12