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Question

If the image of the point (2,1) with respect to a line mirror is (5,2), find the equation of the mirror.

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Solution

Let A=(2,1) & A=(5,2)
The line is mirror.
Line is perpendicular to AA and passes through the midpoint.
Slope of AA=13
Slope of mirror=3
Equation =(y32)=3(x72)
y32=3x+212
2y3=6x+21
6x+2y24=0
3x+y12=0


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